Permutation & Combination Calculator — nPr and nCr Formulas
Calculate permutations (nPr) and combinations (nCr) instantly. Learn the factorial formulas, when order matters, with lottery, card, and seating examples.
Here's the classic stumbling block: you're counting arrangements and you know whether order matters — but you're not sure which formula to reach for. Permutations and combinations are both about choosing from a group, with one key difference. Calculate both with the CalcHub Permutation & Combination Calculator.
The Core Difference
Permutation (nPr): Order matters. Choosing first, second, and third place is different from choosing third, first, and second. Combination (nCr): Order doesn't matter. Choosing teammates {Alice, Bob, Carol} is the same regardless of who you pick first.A useful way to remember: your PIN code is a permutation (order matters). Your pizza toppings are a combination (doesn't matter what order they're listed).
Permutation Formula
$$P(n, r) = \frac{n!}{(n-r)!}$$
Where n is the total number of items and r is how many you're selecting.
Example: How many ways can 3 runners finish in 1st, 2nd, and 3rd from a field of 8?P(8, 3) = 8! / (8−3)! = 8! / 5! = (8 × 7 × 6 × 5!) / 5! = 336 ways
Combination Formula
$$C(n, r) = \frac{n!}{r!(n-r)!} = \binom{n}{r}$$
Example: How many ways can you choose 3 people from a group of 8 to form a committee?C(8, 3) = 8! / (3! × 5!) = (8 × 7 × 6) / (3 × 2 × 1) = 336 / 6 = 56 ways
The ratio P(8,3) / C(8,3) = 336 / 56 = 6 = 3! — exactly the number of ways to arrange 3 chosen items. This makes sense: every combination corresponds to 3! permutations.
Factorial Reference Table
| n | n! |
|---|---|
| 0 | 1 |
| 1 | 1 |
| 2 | 2 |
| 3 | 6 |
| 4 | 24 |
| 5 | 120 |
| 6 | 720 |
| 7 | 5,040 |
| 8 | 40,320 |
| 10 | 3,628,800 |
| 12 | 479,001,600 |
Real-World Examples
Lottery (Combination): India's lottery picks 6 numbers from 1–49. C(49, 6) = 49! / (6! × 43!) = 13,983,816 possible tickets. Order doesn't matter — matching the same 6 numbers wins regardless of draw order. Password (Permutation): A 4-digit PIN from digits 0–9, no repeats. P(10, 4) = 10!/6! = 10 × 9 × 8 × 7 = 5,040 combinations Card Hands (Combination): 5-card poker hand from 52 cards. C(52, 5) = 52! / (5! × 47!) = 2,598,960 possible hands Seating Arrangements (Permutation): 5 people in 5 chairs. P(5, 5) = 5! = 120 arrangementsPermutations with Repetition Allowed
If items can repeat: n^r
Example: 4-digit PIN allowing repeated digits: 10⁴ = 10,000 possible PINs (0000 through 9999)How do I know if a problem is a permutation or combination?
Ask yourself: if I swap the order of my chosen items, do I get a different result? A different race finish — yes, it's a permutation. A different team roster — no, it's a combination. Phrases like "arrangements," "ranking," "sequence" suggest permutations. "Groups," "teams," "selections," "subsets" suggest combinations.
What does C(n,r) = C(n, n-r) mean?
Choosing 3 items from 10 is equivalent to choosing which 7 items to leave out. So C(10,3) = C(10,7) = 120. This symmetry is also reflected in Pascal's Triangle, where C(n,r) appears at row n, position r.
Why does 0! equal 1?
Mathematically, 0! = 1 makes combinatorics consistent: C(n, 0) = n! / (0! × n!) = 1, which correctly represents "there's exactly one way to choose nothing from a set." It also makes the gamma function and many series expansions work cleanly.